allclose¶

paddle. allclose ( x, y, rtol=1e-05, atol=1e-08, equal_nan=False, name=None ) [source]

Check if all $x$ and $y$ satisfy the condition:

$\left| x - y \right| \leq atol + rtol \times \left| y \right|$

elementwise, for all elements of $x$ and $y$ . This is analogous to $numpy.allclose$ , namely that it returns $True$ if two tensors are elementwise equal within a tolerance.

Parameters

x (Tensor) – The input tensor, it’s data type should be float16, float32, float64.
y (Tensor) – The input tensor, it’s data type should be float16, float32, float64.
rtol (rtoltype, optional) – The relative tolerance. Default: $1e-5$ .
atol (atoltype, optional) – The absolute tolerance. Default: $1e-8$ .
equal_nan (equalnantype, optional) – (bool), attribute 2 for allclose op. Default: False.
name (str, optional) – Name for the operation. For more information, please refer to Name. Default: None.

Returns

The output tensor, it’s data type is bool.

Return type

Tensor

Examples

>>> import paddle

>>> x = paddle.to_tensor([10000., 1e-07])
>>> y = paddle.to_tensor([10000.1, 1e-08])
>>> result1 = paddle.allclose(x, y, rtol=1e-05, atol=1e-08, equal_nan=False, name="ignore_nan")
>>> print(result1)
Tensor(shape=[], dtype=bool, place=Place(cpu), stop_gradient=True,
False)
>>> result2 = paddle.allclose(x, y, rtol=1e-05, atol=1e-08, equal_nan=True, name="equal_nan")
>>> print(result2)
Tensor(shape=[], dtype=bool, place=Place(cpu), stop_gradient=True,
False)
>>> x = paddle.to_tensor([1.0, float('nan')])
>>> y = paddle.to_tensor([1.0, float('nan')])
>>> result1 = paddle.allclose(x, y, rtol=1e-05, atol=1e-08, equal_nan=False, name="ignore_nan")
>>> print(result1)
Tensor(shape=[], dtype=bool, place=Place(cpu), stop_gradient=True,
False)
>>> result2 = paddle.allclose(x, y, rtol=1e-05, atol=1e-08, equal_nan=True, name="equal_nan")
>>> print(result2)
Tensor(shape=[], dtype=bool, place=Place(cpu), stop_gradient=True,
True)